Question

Given that P(E) = 0.38, P(F) = 0.38, and P(E ∩ F) = 0.12. Find P(E ∪ F, how do I work this out?

Answer 1

Answer: The value of P(E∪F) = 0.64.

Step-by-step explanation:

Since we have given that

P(E) = 0.38

P(F) = 0.38

P(E∩F) = 0.12

So, we need to find the P(E∪F).

As we know the formula for the sets.

$P(E\cup F)=P(E)+P(F)-P(E\cap F)\\\\P(E\cup F)=0.38+0.38-0.12=0.64\\\\P(E\cup F)=0.64$

Hence,the value of P(E∪F) = 0.64.