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a_sh-v [17]
3 years ago
11

Create a stem-and-leaf plot for the data set. Enter rows of numbers corresponding to the stems and leaves. 77, 81, 85, 88, 89, 9

0, 92, 95, 97, 100, 100
Mathematics
1 answer:
Shalnov [3]3 years ago
6 0

Answer:

just put a vertical line through it, in front of the 7,8,9,10 and behind the 7,1,0,00. I couldn't do that on here.

Step-by-step explanation:

7 -7

8-1,5,8,9

9-0,2,5,7,

10-00,00

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Manuel incorrectly claimed that the surface area of the cylinder
Andre45 [30]

Answer:

25.9%

Step-by-step explanation:

Since, the actual dimensions of the cylinder is not given we can assume the some dimension to explain the problem

Let us assume the dimension of the cylinder be

radius= 3in

height= 5 in

The expression for the total surface area of a cylinder is

T. S. A. =2πrh+2πr^2

Let us plug in the values to to find TSA

T. S. A. =2×3.14×3×5+2×3.14×3^2

Solving we get

T. S. A. =94.26+56.556

T. S. A. =150.816 in^2

Now let us find the error

we know that error % is calculated as

%error= [actual value-expected value/expected value]×100

%error= [190 -150.816/150.816]×100

%error= [39.184/150.816]×100

%error= 0.259×100

%error= 25.9%

6 0
3 years ago
The volume of a rectangular prism is (x^3 – 3x^2 + 5x – 3), and the area of its base is (x^2 – 2). If the volume of a rectangula
bixtya [17]

Answer:

The height of the prism is equal to h=(x^{3}-3x^{2}+5x-3)/(x^{2}-2)

Step-by-step explanation:

we know that

The volume of a rectangular prism  is equal to

V=Bh

where

B is the area of the base of the prism

h is the height of the prism

In this problem we have

V=x^{3}-3x^{2}+5x-3

B=x^{2}-2

substitute in the formula and solve for h

x^{3}-3x^{2}+5x-3=(x^{2}-2)h

h=(x^{3}-3x^{2}+5x-3)/(x^{2}-2)

3 0
4 years ago
Taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.
Novosadov [1.4K]

Answer:

Step-by-step explanation:

Given that taxi Fares are normally distributed with a mean fare of $22.27 and a standard deviation of $2.20.

For a random single taxi std deviation is 2.20

But for a sample of size 10, std deviation would be

\frac{2.20}{\sqrt{10} }

This would be less than the 2.20

Because std devition is less for sample we get a big z score for the sample than the single.  

As positive values of z increase we find that probability would decrease since normal curve is bell shaped.

So single taxi fare would have higher probability than sample.

B) Here >24.

By the same argument we have z value less for single taxi hence the probability for more than that would be less than that of sample size 10

3 0
3 years ago
He speeds (in MPH) of automobiles traveling in a city are given below:
professor190 [17]

Answer:

Mean speed = 41.3 mph

Step-by-step explanation:

Given that,

The speeds of an automobiles are given below:

20, 35, 42, 52, 65, 49, 24, 37, 23, 41, 50, 58

We need to find the mean speed of the cars.

Mean = sum of observations/ no. of observation

M=\dfrac{20+35+42+52+65+49+24+37+23+41+50+58}{12}\\\\M=41.3

So, the mean speed of the cars is equal to 41.3 mph.

7 0
3 years ago
Write the following equation in standard form:22+52 +4 24 - 220
LekaFEV [45]

Answer:2.78×10^2

Step-by-step explanation:

22+52+424-220

=278

In standard form

=2.78×10^2

6 0
3 years ago
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