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iogann1982 [59]
3 years ago
14

4(-g+3)=16 I need help with this math question

Mathematics
1 answer:
Rudik [331]3 years ago
7 0
-4g + 12 = 16 then -12 on the both side

-4g = 4 then divided by -4, you will get g = -1
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Help ASAP!
Tema [17]

Answer:

B

Step-by-step explanation:

\boxed{area \: of \: sector =  \frac{1}{2} {r}^{2} θ }

Radius= diameter ÷2

r= 32 ÷2

r= 16

\frac{1}{2}  {r}^{2} θ =  \frac{512\pi}{3}

Substitute r= 16,

\frac{1}{2} ( {16}^{2} )(θ) =  \frac{512\pi}{3}

128 \: θ =  \frac{512\pi}{3}  \\ θ =  \frac{512\pi}{3}  \div 128 \\ θ =  \frac{512\pi}{384}

Divide the denominator and numerator by 128:

θ =  \frac{4\pi}{3}

Thus, the answer is B.

3 0
3 years ago
In which line did the student make the first mistake?
Setler [38]
It’s line 4. She subtracted the final from the initial. The distance formula requires you to subtract the initial from the final. That’s the formula for displacement in x and y.
4 0
3 years ago
4. Why does Miss Maudie only have two small cakes instead of three
Rudiy27

Answer:

B

Step-by-step explanation:

She only has two cakes because that's all she bought.

8 0
3 years ago
The sum of the number is 103.the second number is 4 times the third.the third number is 5 more then the first .what are the numb
Zigmanuir [339]

Answer:

13, 18, 72

Step-by-step explanation:

let x-5 represent the first number, since the first number is 5 less than the third number. let x represent the third number. let 4x represent the third number, since it's four times greater than the third number.

set up an equation, and make it equal to 103:

x-5+x+4x=103

solve:

6x-5=103

6x=108

x=18

so, the third number is 18.

the first number is equal to x-5, so:

18-5=13

the second number is equal to 4x, so:

4(18)=72

so, the three numbers are 13, 18, and 72.

4 0
2 years ago
Given: JK tangent, KH=16, HE=12 Find: JK.
Y_Kistochka [10]

Answer: JK=8

Step-by-step explanation:

You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:

JK^2=KE*KH

You know that:

KH=KE+HE

Then KE is:

KE=KH-HE

KE=16-12

KE=4

Now you can substitute the value of KE and the value of KH into  JK^2=KE*KH and solve for JK. Then the result is:

JK^2=4*16\\JK^2=64\\JK=\sqrt{64}\\JK=8

7 0
3 years ago
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