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Elena-2011 [213]
3 years ago
14

Find three consecutive integers such that the sum of the 1st and 3rd is 60.

Mathematics
1 answer:
bija089 [108]3 years ago
5 0
29,30,31 are the numbers
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The table below shows the cube roots of different numbers:
Mila [183]

part A)

\bf \begin{array}{|c|cccccc|ll} \cline{1-7} x&8&27&64&125&&x\\ \cline{1-7} y&\stackrel{\sqrt[3]{8}}{2}&\stackrel{\sqrt[3]{27}}{3}&\stackrel{\sqrt[3]{64}}{4}&\stackrel{\sqrt[3]{125}}{5}&&\sqrt[3]{x} \\ \cline{1-7} \end{array}~\hspace{10em}y = \sqrt[3]{x}

part B)

f(x) = 10 + 20x

so if you rent the bike for a few hours that is

1 hr.............................10 + 20(1)

2 hrs..........................10 + 20(2)

3 hrs..........................10 + 20(3)

so the cost is really some fixed 10 + 20 bucks per hour, usually the 10 bucks is for some paperwork fee, so you go to the bike shop, and they'd say, ok is 10 bucks to set up a membership and 20 bucks per hour for using it, thereabouts.

f(100) = 10 + 20(100) => f(100) = 2010.

f(100), the cost of renting the bike for 100 hours.

4 0
2 years ago
Which of the following graphs has a zero at (-5)?
guapka [62]
Graph B would be the correct answer
6 0
1 year ago
PLEASE HELP PLEASE IM TIMED!!!
inysia [295]

Answer:

9316000000000

Simply move the decimal 12 places to the left.

If this helped please mark as brainiest <3

8 0
2 years ago
Simply 20-3[4(z+1)-6(z-2)]
creativ13 [48]

Answer:

The answer is 6z-28

Step-by-step explanation:

20 - 3[4(z+1) - 6(z-2)]

= 20 - 3(4z+4-6z+12)

= 20 - 3(16 - 2z)

= 20 - 48 + 6z

= 6z - 28

8 0
3 years ago
25x
solmaris [256]

Answer:

option c is correct answer

7 0
2 years ago
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