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vredina [299]
3 years ago
9

Hello please help will give brainliest!

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0
The answer is A. because the first part shows the ratio 3:2 and the other 2 shows equivalent ratios.
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If r is ten more than the square root of l , then r = A) l2 + 10 B) (l + 10)2 C) l + 10 D) l + 10 E) l + 10
stiv31 [10]

Answer:

r=\sqrt {I}+10

Step-by-step explanation:

We first need to know the square root of I then add 10 on that square root since r is 10 more than the square root of I

Therefore,

r=\sqrt {I}+10

4 0
3 years ago
Is 0.212121212121...a rational number because a irrational number does not terminate or repeat?
pentagon [3]
The 21 part repeats

it can be represented as 21/99

it's rational
8 0
3 years ago
In a survey, 2 out of 8 students named math as their favorite subject. Express the rate as a decimal and as a percent.
SVETLANKA909090 [29]

Answer: 0.25 and 25%


Step-by-step explanation:

2/8 is equal to 1/4. 1/4 is the same as 0.25. Move decimal point two spots to the right and BOOM you get 25%.

8 0
3 years ago
Find the area of the triangle. 5 ft 8 ft ​
natima [27]

Answer:

40

Step-by-step explanation:

The formula for area is LxW, in this case it’s 5x8 which is 40.

8 0
3 years ago
Read 2 more answers
Find two unit vectors orthogonal to both given vectors. i j k, 4i k
Maurinko [17]
The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
6 0
3 years ago
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