What is 1 + 1 hhehehehhee

PLEASEEEE HELPPP

soldier1979 [14.2K]

Ik I’m not know help but gee I forgot this just go on google

4 0

3 years ago

Read 2 more answers

Find the distance between the points given (0, -6) and (9, 6)

Valentin [98]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[9-0]^2+[6-(-6)]^2}\implies d=\sqrt{(9-0)^2+(6+6)^2} \\\\\\ d=\sqrt{9^2+12^2}\implies d=\sqrt{225}\implies d=15$

3 0

4 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago

Which of the following is not a polynomial identity?

olga_2 [115]

Answer:

Option B

Step-by-step explanation:

Option A

a² - b² = (a+ b)(a - b)

It's a polynomial identity.

Option B

a³ + b³ = (a - b)(a² - ab + b²)

It's not a polynomial identity.

Because the identity is,

a³ + b³ = (a + b)(a² - ab + b²)

Option C

a³ - b³ = (a - b)(a² + ab + b²)

It's a polynomial identity.

Option D

(a²+ b²)(c² + d²) = (ac - bd)² + (ad + bc)²

= a²c² - 2abcd + b²d² + a²d² + b²c² + 2abcd

= a²c² + b²c² + b²d² + a²d²

= c²(a² + b²) + d²(a² + b²)

= (a²+ b²)(c² + d²)

Therefore, it's a polynomial identity.

Option B will be the answer.

7 0

3 years ago

During the first year she owned her car, Leslie spent $756 on repairs and maintenance. She spent $1,580 the second year she owne

Drupady [299]

Answer:

109% of increase

Step-by-step explanation:

In order to know the increase in the percentage, we can do this in various methods, however let's follow the method using only rule of 3; you can also do it by the variation index, however, rule of 3 is easier.

First, we need to know the difference between 756$ and 1580$:

1580 - 756 = 824$

Now let's set the rule of three, assuming that 756 is 100% innitial:

756$-------->100%

824$--------> X

Solving for X:

X = 824 * 100 / 756 = 109.9947%

And if you round this number: 109%

8 0

4 years ago