AD = 42-x
The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides ⇒
AB/BC = AD/DC
36/27 = (42-x)/x
36x = 27(42-x)
36x = 1134 - 27x
36x + 27x = 1134
63x = 1134
x = 1134/63
x = 18
The sum of the first n terms in a geometric sequence given the first term (a1) and the common ratio (r) is calculated through the equation,
<span>Sn </span>= (<span><span><span>a1</span>(1−<span>r^n</span>) / (</span><span>1−r)
Substituting the known terms,
Sn = (20)(1 - (1/4)^4)) / (1 - 1/4)
Sn = 26.5625
Thus, the sum of the first four terms is 26.5625. </span></span>
Answer:
167 243/386
Step-by-step explanation:
For steps, use this link:
https://mathsolver.microsoft.com/en/solve-problem/64705%20%60div%20%20386
Answer:
a*2+b*2+c*2+d
Step-by-step explanation:
If i's meant to be Pythagorean theorem, a*a+b*b=c*c
The trig functions that you need to deal with are
Sine
Cosine
Tangent
Cotangent
Cosecant
Secant
You need to write a single expression using all six trig functions such that the value of the expression equals 3.
To make this as simple as possible, the first thing I would do is look up the values of these functions and identify which ones are equal to either 1/2 or 1.0 or 2.0
sin(30º) = 1/2
sin(90º) = 1
cos(0º) = 1
cos(60º) = 1/2
tan(45º) = 1
csc(30º) = 2
csc(90º) = 1
sec(0º) = 1
sec(60º) = 2
cot(45º) = 1
If we only had to use three trig functions (sin, cos, tan), one possibility is
tan(45º) + cos(0º)/sin(30º) = 1 + 1/(1/2) = 1 + 2 = 3
noticed how I chose one each of the required functions and the operations so that the result = 3.
Now it is up to you to figure out how to combine all six trig functions so that they equal zero. There are many possibilities for you to choose from..
