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ruslelena [56]
3 years ago
12

The women’s heptathlon in the Olympics consists of seven track and field events: the 200-m and 800-m runs, 100-m high hurdles, s

hot put, javelin, high jump, and long jump. In the 2000 Olympics, the best 800-m time, run by Gertrud Bacher of Italy, was 8 seconds faster than the mean. The winning long jump by the Russian Yelena Prokhorova was 60 centimeters longer than the mean. Bacher’s winning 800-m time of 129 seconds was 8 seconds faster than the mean qualifying time of 137 seconds (the standard deviation of the qualifying times was 5 seconds). Prokhorova’s winning long jump was 60cm longer than the average 6-m jump (Note: the standard deviation of the long jumps was 30 cm). Which performance is more outstanding (and hence deserves more points when computing their overall score)? Explain.
Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

Answer: Prokhorova is more outstanding.

Step-by-step explanation: To compare scores from different distributions, first standardize it:

z-score = \frac{x-\mu}{\sigma}

where

x is the individual mean you want to compare

μ is the mean of the population

σ is standard deviation

For <u>Gertrud Bacher</u>:

z-score = \frac{129-137}{5}

z-score = -1.6 (s)

The negative sign indicates Bacher's mean is less than the mean

For <u>Yelena Prokhorova</u>:

z-score = \frac{660-600}{30}

z-score = 2 (cm)

The positive sign indicates Prokhorova's mean is more than the mean.

Using z-score table, you determine the percentiles are:

For Bacher: Percentile = 5.5%

For Prokhorova: Percentile = 97.7%

Bacher's percentile means she is above 5.5% of the participants, while Prokhorova is 97.7% above the other competitors, which means Prokhorova have a better performance and deserves more points.

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2989024

——————————

You have  y  as an implicit function of  x:

sin(xy) – x = 0


Use implicit differentiation. As  y  is a function of  x, then you must apply the chain rule there:

  d                                 d
—— [ sin(xy) – x ]  =  —— (0)
 dx                               dx


  d                           d               d
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 dx                         dx             dx

  d
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 dx

  d
—— [ sin(xy) ]  =  1
 dx
 
                   d
cos(xy)  ·  —— (xy) = 1
                  dx


Now, apply the product rule for that last derivative:

\mathsf{cos(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\&#10;\mathsf{cos(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\&#10;\mathsf{y\,cos(xy)+x\,cos(xy)\cdot \dfrac{dy}{dx}=1}


              dy
Isolate  —— :
              dx

                   dy
x cos(xy) · ——  =  1 – y cos(xy)
                   dx


Assuming  x cos(xy) ≠ 0,

 dy          1 – y cos(xy)
——  =  ————————    <———    this is the answer.
 dx            x cos (xy)


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