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Finger [1]
3 years ago
9

What is the solution to the equation fraction 1 over 6 x = 2? A. x = fraction 1 over 12 B. x = fraction 1 over 3 C. x = 3 D. x =

12
Mathematics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

pic plz

Step-by-step explanation:

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The answer is 70 people will attend
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Using quadratic form 6x^2-8x+3=0
LenaWriter [7]

x=8+sqrt-8/12, x=8-sqrt-8/12

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What will be the length of the battery?
kobusy [5.1K]

Answer:

:) 17

Step-by-step explanation:

68 = 4 x L

68 div by 4 = 17

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6 0
2 years ago
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Y=2x+9 y=4x-9 Solve the system of equations.
Deffense [45]

Answer:

Your solution is (9, 27) or x = 9, y = 27

Step-by-step explanation:

y = 2x + 9

y = 4x - 9

We can see that both of these equations equal y, so we can set them equal to each other.

2x + 9 = 4x - 9

Add 9 to both sides.

2x + 18 = 4x

Subtract 2x from both sides.

18 = 2x

Divide both sides by 2.

9 = x

Now we want to find y. To do this, plug x = 9 back into one of the original equations.

y = 2(9) + 9

Multiply.

y = 18 + 9

Add.

y = 27

Your solution is (9, 27)

Check your answer by plugging x = 9 and y = 27 back into the original equations.

y = 2x + 9

27 = 2(9) + 9

27 = 18 + 9

27 = 27

y = 4x - 9

27 = 4(9) - 9

27 = 36 - 9

27 = 27

Your answer is correct.

Hope this helps!

3 0
3 years ago
Read 2 more answers
Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?
BaLLatris [955]

Answer:

Vertex = (\frac{1}{2},\frac{7}{4})

Step-by-step explanation:

Given

f(x) = x^2 - x +2

Required

The vertex

We have:

f(x) = x^2 - x +2

First, we express the equation as:

f(x) = a(x - h)^2  +k

Where

Vertex = (h,k)

So, we have:

f(x) = x^2 - x +2

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

f(x) = x^2 - x +2

f(x) = x^2 - x + (-\frac{1}{2})^2+2  -(-\frac{1}{2})^2

f(x) = x^2 - x + \frac{1}{4}+2  -\frac{1}{4}

Expand

f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2  -\frac{1}{4}

Factorize

f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2  -\frac{1}{4}

Factor out x - 1/2

f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2  -\frac{1}{4}

f(x) = (x - \frac{1}{2})^2+2  -\frac{1}{4}

f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}

f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}

Compare to: f(x) = a(x - h)^2  +k

h = \frac{1}{2}

k = \frac{7}{4}

Hence:

Vertex = (\frac{1}{2},\frac{7}{4})

8 0
3 years ago
Read 2 more answers
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