<span>Determine the values of x on which the function f(x)=2x^2-x-15/4x^2-12x is discontinuous and verify the type of discontinuity at each point.
A.There is a vertical asymptote at 0 and a hole at 3.
B.There are vertical asymptotes at -5/2 & 0 and a hole at 3.
C.There is a vertical asymptote at 3 and a hole at 0.
D.There are vertical asymptotes at 0 & 3.
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Result:
(-7/4)x^2-13x
The roots are:
x= -52/7
x=0
See attached pictures.
Answer:
12.16 it's a continues answer tho
Answer:
18
Step-by-step explanation:
w varies directly with z, let k be the constant of proportionality, hence this can be represented by the equation:
w = kz
When z = 4, w = 12, hence we need to find the value of the constant of proportionality, substituting:
12 = 4k
Dividing both sides by 4:
12/4 = 4k/4
k = 3
Therefore the equation becomes:
w = 3z
The value of w when z = 6 is given as:
w = 3(6)
w = 18
The number 5760 because when divided by 12 you get an answer of 480 and with 24 it is 240 and with 30 is 192.
Answer:
1.02
Step-by-step explanation: