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GalinKa [24]
3 years ago
8

Where I had $480 he used 2/3 of it to buy an electric van he also bought a tea set for $60 how

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0

2/3 of 480 is 480 divided by 3 and that number times 2, which is 320. The man or woman probably used $60 of this to buy the tea set, which leaves them with $260.

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In 10⁵, the number 10 is the?​
xxMikexx [17]

Answer:

The number 10 is the base

8 0
4 years ago
The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a
Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = \sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}

                 = {^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}  + .......+ {^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}

                = 0.04541 + ......+0.0000002079

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⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0
3 years ago
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igor_vitrenko [27]

Step-by-step explanation:

I am not sure what you mean by "solve".

I assume you mean simplify the expression.

and then it is very tricky to find the true original expression the way you typed it.

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so, this is the same as

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this would give us in total

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to do the subtraction we need to bring both fractions to the save denominator (lower part).

it seems to me the easiest one would be 10m.

so,

2×(5m + 2)/10m - m×(9m + 3)/10m =

= (10m + 4)/10m - (9m² + 3m)/10m =

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if we want to transform this back to a sum of fractions :

4/10m - (9m² - 7m)/10m = 2/5m - (9m - 7)/10

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It was easy!

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