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juin [17]
3 years ago
15

What is the approximate volume of a cone with a height of 12 in. and radius of 9 in.?

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0

Answer: The answer is 1017.88in³

Step-by-step explanation:

swat323 years ago
4 0
The answer would be 1017.88 in³. Use the volume for cones ( 1/3 times pi times radius times height) so 1/3*3.14*9*12 in which would be 1017.88 in³ hope it helps!
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Which equation can be used to solve for x in the following diagram?
Setler [38]

∑ Hey, petalssquad10 ⊃

Answer:

( 10 x + 10 ) = 110

Step-by-step explanation:

As you can see this following diagram shown a vertical angles which  are angles that are opposite of each other when two lines cross. You can also see it kind of look like a "x". Vertical angles also means that they have the same angle measure. A example is if this angle is "110" then the other sides equal to "110''.

Hence, the equation we can be used to solve for x in the following diagram is:

( 10 x + 10 ) = 110

You can also refer to the image below:

<u><em>xcookiex12</em></u>

<u><em></em></u>

<em>8/18/2022</em>

6 0
2 years ago
Which of the following results in the expressions 0.43 times 52 ?
Mariulka [41]
The answer is 43% of 52. So D
5 0
3 years ago
Read 2 more answers
Find tan(30) (its a right triangle)
Travka [436]
Use the 30-60-90 triangle.

Tan is opposite over adjacent.

\frac{1}{ \sqrt{3} }
Square roots cannot be on the bottom.

\frac{1}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }
The bottom cancel out the square root bar.

Your answer is:

\frac{ \sqrt{3} }{3}
(It's best to memorize the 30-60-90 and the 45-45-90 triangles during trigonometry. It helps a lot.)

Hope this helps!

:)

8 0
3 years ago
the angle theta is in the second quadrant and cos theta = -2/√29 determine possible coordinates for point P on the terminal arm
Gekata [30.6K]

\cos(\theta)=-\frac{2}{\sqrt{29}} and $\theta$ lies in $2^{\text{th}}$ quadrant.

where, $x-$ coordinate is negative, and $y-$ coordinate is positive

so it can't a.

now, cosine means, side adjacent over the hypotenuse, in Cartesian plane, that will be $x-$ coordinate over the distance from origin.

Assume the triangle , with base $2$ units and hypotenuse $\sqrt{29}$ and it's in second quadrant. (so \cos(\theta)=-\frac{2}{\sqrt{29}})

now, the leftmost point on $x-$ axis is , obviously $(-2,0)$

and by Pythagoras theorem, we can find the perpendicular side, that will be $y^2=(\sqrt{29})^2-(2)^2\implies y=5$

so the coordinates of the upper vertex is $(-2,5)$, each point lying on this "ray" should have equal ratio of respective coordinates. i.e. $\frac25=\left|\frac xy\right| $

and it should lie on second quadrant, so $x<0 \, y>0$

Option d satisfies this.

6 0
3 years ago
The difference of 4 from 12
olga55 [171]

Answer:

thw

the difference of 4 from 12

= 8

7 0
3 years ago
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