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2 years ago

Ming drew the model to represent the equation 24+12=_x(8+4). What is the missing value in Ming's equation 3 4 12 24

Mathematics

1 answer:

Anika [276]2 years ago

8 0

Answer:

3 is the missing value

Step-by-step explanation:

Given

$24 + 12 = \_ * (8 + 4)$

Required

Complete the blank

The model is not given; but the question can still be solved.

We have:

$24 + 12 = \_ * (8 + 4)$

Add 8 to 4

$24 + 12 = \_ * 12$

Add 24 to 12

$36= \_ * 12$

Divide both sides by 12

$3= \_$

Rewrite as:

$\_ = 3$

Hence, the blank will be completed with 3

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Explain how to estimate 368+231 two different ways

cestrela7 [59]

You can estimate 368 + 231 by rounding the numbers to nearest hundreds
Which is 400 + 200
You can estimate 368 + 231 by rounding the numbers to the nearest tens
Which is 370 + 230

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3 years ago

Read 2 more answers

16. Simplify the expression.<br> (6 + 47) + (4 + 61)<br> -10 - 10<br> 10 + 10i<br> 201<br> 10 - 10

Kobotan [32]

The answer should be 10 + 10i. Hope that helps.

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2 years ago

Please help answer this!!!

NNADVOKAT [17]

Answer:

49) $12\,b^4$

50) $200\,x^6$

Step-by-step explanation:

Use the properties of exponent to reduce this expressions:

a) $3\,b\,*\,4 \,b^3=(3\,*\,4)\,(b\,*\,b^3)=12\,b^{(1+3)}=12\,b^4$

b) $5\,x^2\,*\,8\,x\,5\,*\,x^3=(5\,*\,8\,*\,5)\,(x^2\,*\,x\,*\,x^3)=200\,x^{(2+1+3)}= 200\,x^6$

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2 years ago

There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e

notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

$P_{1}=\frac{7 \ girls}{9 \ students}$

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$

Therefore, there's 28% probability that every student in the group is a girl.

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2 years ago

What is 1/4 times 7/9?

denpristay [2]

Answer:

7/36

Step-by-step explanation:

1/4 × 7/9 = 7/36 Hope that helps!

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2 years ago