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2 years ago

Hi I need help ASAP

Mathematics

2 answers:

Katarina [22]2 years ago

7 0

Answer:

3/5

Step-by-step explanation:

12 x

--- = ----

20 5

how do you get from 20 to 5? divide by 4.

12 divided by 4 is 3. The answer is 3/5.

Just think about proportions.

ella [17]2 years ago

4 0

So we know that 12/20 = ?/5.

20 = 5 * 4 OR 5 = 20/4.

So we divide 12 by 4 to find the answer for ?

12 / 4 = 3.

So 3/5 = 12/20

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hich function has a range of {y|y ≤ 5}? f(x) = (x – 4)2 + 5 f(x) = –(x – 4)2 + 5 f(x) = (x – 5)2 + 4 f(x) = –(x – 5)2 + 4

Brums [2.3K]

Answer:

$f(x)=-(x-4)^2+5$

Step-by-step explanation:

The function $f(x)=-(x-4)^2+5$ has the vertex at $(4,5)$ .

Since $a=-1\:$ , the graph of the function is a maximum graph.

The highest y-value is the y-coordinate of the vertex which is 5.

Therefore the range is { $y|y\le 5$ }

Therefore the correct answer is B.

6 0

2 years ago

What are the factors of 2a³ + a² + 2a + 1?

morpeh [17]

Answer:

The answer is (a²+1)(2a+1)

4 0

1 year ago

What is the scale factor of two similar pyramids with volume of 13824 cubic feel and 216 cubic feet?

velikii [3]

Answer: The scale factor is 4

Step-by-step explanation:

We know that the pyramids are similar. The volume of one of these pyramids is 13,824 cubic feet and the volume of the other one is 216 cubic feet. Then:

$V_1=13,824ft^3\\V_2=216ft^3$

By Similar solids theorem, if two similar solids have a scale factor of $\frac{a}{b}$ , then corresponding volumes have a ratio of $\frac{a^3}{b^3}$

Then:

$\frac{V_1}{V_2}=\frac{a^3}{b^3}$

Knowing this, we can find the scale factor. This is:

$\frac{13,824}{216}=\frac{a^3}{b^3}\\\\\frac{13,824}{216}=(\frac{a}{b})^3\\\\\frac{a}{b}=\sqrt[3]{\frac{13,824}{216}}\\\\scale\ factor=\frac{a}{b}=4$

3 0

2 years ago

(b) In the figure below, m 2AEB= 55° and m AB = 60°. Find m CD.<br><br> m CD =

RUDIKE [14]

Answer:

47 degrees

Explanation:

your welcome

4 0

1 year ago

X = -2y + 300 3y = 800 - 4x

devlian [24]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}x=-2y+300&(1)\\3y=800-4x&(2)\end{array}\right\\\\\text{Substitute (1) to (2):}\\\\3y=800-4(-2y+300)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\3y=800+(-4)(-2y)+(-4)(300)\\\\3y=800+8y-1200\\\\3y=8y-400\qquad\text{subtract}\ 8y\ \text{from both sides}\\\\-5y=-400\qquad\text{divide both sides by (-5)}\\\\y=80\\\\\text{Put it to (1):}\\\\x=-2(80)+300\\\\x=-160+300\\\\x=140$

8 0

2 years ago

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Hi I need help ASAP​

Hi I need help ASAP