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kolbaska11 [484]
3 years ago
9

Which of the following is NOT a requirement to conduct a goodness-of-fit test? Question 1 options: a) For each category, the obs

erved frequency is at least 5. b) The sample data consist of frequency counts for each of the different categories c) The sample is simple random sample. d) For each category, the expected frequency is at least 5.
Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

The answer is A.) For each category, the observed frequency is at least 5.

Step-by-step explanation:

Just took the test.

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What is the differences in length between the shortest and longest crayons​
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3 years ago
Assume that hybridization experiments are conducted with peas having the property that for​ offspring, there is a 0.75 probabili
ivolga24 [154]

Answer:

(a) The mean and the standard deviation for the numbers of peas with green pods in the groups of 36 is 27 and 2.6 respectively.

(b) The significantly low values are those which are less than or equal to 21.8. And on the other hand, the significantly higher values are those which are greater than or equal to 32.2.

(c) The result of 15 peas with green pods is a result that is significantly​ low value.

Step-by-step explanation:

We are given that hybridization experiments are conducted with peas having the property that for​ offspring, there is a 0.75 probability that a pea has green pods.

Assume that the offspring peas are randomly selected in groups of 36.

The above situation can be represented as a binomial distribution;

where, n = sample of offspring peas = 36

            p = probability that a pea has green pods = 0.75

(a) The mean of the binomial distribution is given by the product of sample size (n) and the probability (p), that is;

                    Mean, \mu  =  n \times p

                                    =  36 \times 0.75 = 27 peas

So, the mean number of peas with green pods in the groups of 36 is 27.

Similarly, the standard deviation of the binomial distribution is given by the formula;

            Standard deviation, \sigma  =  \sqrt{n \times p \times (1-p)}

                                                  =  \sqrt{36 \times 0.75 \times (1-0.75)}

                                                  =  \sqrt{6.75}  =  2.6 peas

So, the standard deviation for the numbers of peas with green pods in the groups of 36 is 2.6.

             

(b) Now, the range rule of thumb states that the usual range of values lies within the 2 standard deviations of the mean, that means;

          \mu - 2 \sigma  =  27 - (2 \times 2.6)

                       =  27 - 5.2 = 21.8

          \mu + 2 \sigma  =  27 + (2 \times 2.6)

                       =  27 + 5.2 = 32.2

This means that the significantly low values are those which are less than or equal to 21.8.

And on the other hand, the significantly higher values are those which are greater than or equal to 32.2.

(c) The result of 15 peas with green pods is a result that is a significantly​ low value because the value of 15 is less than 21.8 which is represented as a significantly low value.

5 0
3 years ago
Mr. Valdez puts $10,000 in a retirement account and does not make any deposits or withdrawals. The table below shows the amount
Anton [14]

Answer:

The answer on edge. is f(x) =  9,974.73  ( 1.05 )x

Step-by-step explanation

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6 0
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