Answer:
The answer is below
Step-by-step explanation:
Let a complex z = r(cos θ + isinθ), the nth root of the complex number is given as:
Given the complex number z = 81(cos(3π/8)+isin(3π/8)), the fourth root (i.e n = 4) is given as follows:
![z_{k=0}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(0)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(0)\pi}{4} ))=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})] \\z_{k=0}=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})]\\\\z_{k=1}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(1)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(1)\pi}{4} ))=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})] \\z_{k=1}=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})]\\\\](https://tex.z-dn.net/?f=z_%7Bk%3D0%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%280%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%280%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D0%7D%3D3%5Bcos%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B3%5Cpi%7D%7B32%7D%29%5D%5C%5C%5C%5Cz_%7Bk%3D1%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%281%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%281%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D1%7D%3D3%5Bcos%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B19%5Cpi%7D%7B32%7D%29%5D%5C%5C%5C%5C)
![z_{k=2}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(2)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(2)\pi}{4} ))=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})] \\z_{k=2}=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})]\\\\z_{k=3}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(3)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(3)\pi}{4} ))=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})] \\z_{k=3}=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})]](https://tex.z-dn.net/?f=z_%7Bk%3D2%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%282%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%282%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D2%7D%3D3%5Bcos%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B35%5Cpi%7D%7B32%7D%29%5D%5C%5C%5C%5Cz_%7Bk%3D3%7D%3D81%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%28cos%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%283%29%5Cpi%7D%7B4%7D%20%29%2Bisin%28%5Cfrac%7B%5Cfrac%7B3%5Cpi%7D%7B8%7D%20%20%2B2%283%29%5Cpi%7D%7B4%7D%20%29%29%3D3%5Bcos%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%29%5D%20%5C%5Cz_%7Bk%3D3%7D%3D3%5Bcos%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%20%29%2Bisin%28%5Cfrac%7B51%5Cpi%7D%7B32%7D%29%5D)
Answer:
9
Step-by-step explanation:
5+4=9
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
Answer:
3x^2 -7x +2
Step-by-step explanation:
(15x^2 -35x+10) ÷5
(15/5x^2 -35/5x+10/5)
3x^2 -7x +2
This will factor
(3x-1) (x-2)
Answer:
The correct answer is: " x > 2 " .
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Step-by-step explanation:
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Given the inequality:
" 6x > 12 " ;
Solve in terms of "x" :
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Divide each side of the inequality by "6" ;
to isolate "x" on one side of the inequation; & to solve in terms of "x" ;
→ " 6x / 6 > 12 / 6 " ;
to get:
→ " x > 2 " .
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Hope this is helpful to you.
Best wishes to you in your academic pursuits
— and within the "Brainly" community!
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