Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter=
=35
Total no of ways =
=126
=
=
Answer: imma say 1
Step-by-step explanation: sorry if wrong
Twice (2 times) the difference (subtraction) of a number (y) and 7 equals 3.
2*(y-7) = 3
hope this helps :)
Answer:
1. 13+18+13+14+13+16+14+21+13
= 145/9
=16.11
2. Range =145
3. Mode =13
4. Median =14
Step-by-step explanation: