Question

Carrots sell for $2.10 per pound, and crackers sell for $2.90 per pound. Glen bought some carrots and some crackers. The total weight was 2.3 pounds and cost $6.03.
How many pounds of carrots and how many pounds of crackers did Glen buy?

Note: Please give a direct answer

Answer 1

Let carrots be represented by A and crackers be represented by B


Quantity equation:
Total quantity = amount of carrots + amount of crackers
2.3 = A + B
A = 2.3 - B


Cost equation:
Total cost = amount of carrots x cost of carrots + amount of crackers x cost of crackers
6.03 = 2.1A + 2.9B

Substituting the value of A:
6.03 = 2.1(2.3 - B) + 2.9B
B = 1.5 lb

A = 2.3 - 1.5
A = 0.8 lb

Glen bought 0.8 pounds of carrots and 1.5 pounds of crackers.

Answer 2

The answer is
carrots - 0.8 pounds
crackers - 1.5 pounds


x - the weight of carrots
y - the weight of crackers
The total weight was 2.3 pounds: x + y = 2.3

Carrots sell for $2.10 per pound: 2.10x
Crackers sell for $2.90 per pound: 2.90y
The total cost was $6.03: 2.10x + 2.90y = 6.03

x + y = 2.3
2.10x + 2.90y = 6.03
_________
x = 2.3 - y
2.10x + 2.90y = 6.03
_________
2.10(2.3 - y) + 2.90y = 6.03
4.83 - 2.10y + 2.90y = 6.03
4.83 + 0.80y = 6.03
0.80y = 6.03 - 4.83
0.80y = 1.20
y = 1.20y : 0.80
y = 1.5 pounds

x = 2.3 - y = 2.3 - 1.5
x = 0.8 pounds