Answer:
Step-by-step explanation:
Given
When mass = 4kg; Acceleration = 15m/s²
Required
Determine the acceleration when mass = 10kg, provided force is constant;
Represent mass with m and acceleration with a
The question says there's an inverse variation between acceleration and mass; This is represented as thus;
Convert variation to equality
; Where F is the constant of variation (Force)
Make F the subject of formula;
When mass = 4kg; Acceleration = 15m/s²
When mass = 10kg; Substitute 60 for Force
Divide both sides by 10
<em>Hence, the acceleration is </em><em />
2 is to 4 because 64/8 is 8. 4/2 is 2. 2 x 2 is in proportion to 8 x 8
1 yard=3 feet
4yards= 4•3= 12 feet
Perimeter of a square = 4•side = 12 so side of the square is 3 feet
Area of square = 3•3=9 Square feet
Answer:
(x -2) (x- 8) (x+7)
Step-by-step explanation:
Answer:
17.37
Step-by-step explanation:
y varies inversely as the square root of x
Mathematically:
y = k.root x
We first find k here
To find k, we were made to know that y is 21 and x = 361
k = y/root.x
k = 21/root. 361
k = 21/19
now what is y when x = 247
From y = k.root x
y = 21/19 * root 247
y= 21/19 * 15.72
y = 17.37
