Make a system of equations.


Plug in 2d for 'q' in the first equation:


Multiply:

Combine like terms:

Divide 0.60 to both sides:

Now plug this into any of the two equations to find 'q':



So she has 10 dimes and 20 quarters.
Answer: D
Step-by-step explanation:
You need a calculator for this cause the numbers are really large. I used a fx-9860GII Casio calculator. I put the equations on the graph mode. And then I got the x➡️0 for both equations.
I got x=0, y=5000 for the first equation
x=0, y=5200 for the new one.
You can see the y is (5200-5000)=200 more than the old equation. As the x is 0 for both that means the new one moved 200 up for the new one. It goes up cause its positive number .
I put the pictures so you can understand what I'm saying.
Answer:
Area 14 = PQRS + UVW; Area 16 = ABCD + EFG
Step-by-step explanation:
PQRS: A = lw = 7 × 2 = 14
ABCD: A = lw = 4 × 4 = 16
UVW: A = ½bh = ½ × 7 × 4 = 14
EFG: A = ½bh = ½ × 8 × 4 = 16
Area 14 = PQRS + UVW
Area 16 = ABCD + EFG
Answer:
Step-by-step explanation:
Given the inequality
|x|> 1
The modulus of x shows that x can be both positive and negative value.
If x is positive:
x>1
1<x
If x is negative:
-x>1
Multiplying both sides of the inequality by minus will change the inequality sign
x < -1
Combining both inequalities:
1<x<-1
Find the position on the number line in the attachment