Answer:
Step-by-step explanation:
Given y = coskt
y' = -ksinkt
y'' = -k²coskt
Substitute this y'' into the expression 25y'' = −16y
25(-k²coskt) = -16(coskt)
25k²coskt = 16(coskt)
25k² = 16
k² = 16/25
k = ±√16/25
k = ±4/5
b) from the DE 25y'' = −16y
Rearrange
25y''+16y = 0
Expressing using auxiliary equation
25m² + 16 = 0
25m² = -16
m² = -16/25
m = ±4/5 I
m = 0+4/5 I
Since the auxiliary root is complex number
The solution to the DE will be expressed as;
y = Asinmt + Bsinmt
Since k = m
y = Asinkt+Bsinkt where A and B are constants
2m + 2p = 16 Subtract 2m from both sides
2p = 16 - 2m Divide both sides by 2
p = 8 - m
Answer:
1. (x,y)→(y,-x)
2. (x,y)→(-y,x)
3. (x,y)→(-x,-y)
Step-by-step explanation:
1. Rotation 90° clockwise (or 270° counterclockwise) about the origin changes x into y and y into -x, so it has the rule
(x,y)→(y,-x)
2. Rotation 90° counterclockwise (or 270° clockwise) about the origin changes x into -y and y into x, so it has the rule
(x,y)→(-y,x)
3. Rotation 180° clockwise about the origin changes x into y and y into -x, so it has the rule
(x,y)→(-x,-y)
Here you can apply rotation by 90° clockwise twice, so
(x,y)→(-y,x)→(-x,-y)
Answer:
x=2-y/2
y=12/7-6x/7
Step-by-step explanation:
I believe one answer could be (4x4)=16-10=6+12=18+10=28-4=24?
