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Volgvan
3 years ago
9

Find the first three terms of this sequence tn=4n²+2

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

Step-by-step explanation:

finding the first term by putting n=1

t(1)=4.(1)^{2} +2 = 4.1 +2 = 4+2 = 6

finding the second term by putting n=2

t(2)=4.(2)^{2} +2 = 4.4 +2 = 16+2 = 18

finding the third term by putting n=3

t(3)=4.(3)^{2} +2 = 4.9 +2 = 36+2 = 38

hence first three terms are:

               6,18,38,......,4n^{2} +2

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