Divide
7/12 = <span>.583
We get answer: </span><span>D. .583</span>
I believe it would be 38.1
<span>Let b= speed of boat in still water
Let c= speed of current
Upstream
Speed is ; b-c
d u=(b-c)* t u
Downstream
speed is ; b+c
d d=(b+c)*t d
given:
d u=18
t u=3
d d=24
t d=2
------------------
(1) 18=(b-c)*3
(2) 24=(b+c)*2
and
(1) 18=3b-3c
(2) 24=2b+c
Multiply both sides of (1) by 2
Multiply both sides of (2) by 3
(1)
(2)
Add (1) and (2)
And, from (1),
18=3*9-3c
3c=27-18
3c=9
c=3
The speed of the boat in still water is 9 mi/hr
The speed of the current is 3 mi/hr
check:
(1) 18=(9-3)*3
(2) 24=(9+3)*2
and
(1) 18=16*3
18=18
(2) 24=24
</span>
The Statement:
AB is a Diameter is wrong because a Diameter is a straight line passing from side to side through the center. In this case it is a Chord because <span> it is a straight line segment whose endpoints both lie on the </span><span>circle.
ST,SP and Sq are radius this is true becuase </span><span> they are all lines that start from any point of the circumference and end at the center of the </span><span>circle
SQ= 12 cm this is false because SQ is a radius and SQ=ST, ST=6cm
PQ=12 cm this is true because PQ is a diameter</span>
Step-by-step explanation:
TALA RHYTHMIC PATTERNS
ACTIVITY 2: LET'S DO TALA
kind of membranophones/percussion instruments found at home for tapping. Record your
Directions: Perform the following tala rhythmic patterns using the given legend. Use any
performance using any recorder and send it to your
INSTRUMENTS AT HOME
MANJIRA
TIN CANS
1 2 3 4 5 6
х
1 2 3 4 5 6 7 8 9 10 11 12
GHATAM
PAL
X
х
0 X
TABLA
1 2 3 4 5 6 7 8 9 10
BOX
x xox
