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nlexa [21]
3 years ago
12

Help me plz? I have no clue how

Mathematics
1 answer:
a_sh-v [17]3 years ago
5 0
Take 2 points
(3, 9) and (0, 3)
Slope = (Y2 -Y1) ÷ (X2 -X1)
<span>Slope = (3-9) / (0-3)
</span><span>Slope = -6 / -3
</span><span>Slope = 2

The equation will have the form    </span><span>y = mx + b</span>
We can rearrange this to   b = y -mx
Let's take one of the points (3, 9) and the slope (m) and enter it into the formula:
b = -9 -2*3
b= -3
Now we enter all that data into b = y -mx
and get
y = 2x -3


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A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

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Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

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The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

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b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

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4 years ago
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Lets say a² = (\frac{1}{4}) ^2   and  c² = ((\frac{1}{3} )^2

b² = c² - a²

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So b = \sqrt{1/144} = \frac{1}{12} units.

So the other side = \frac{1}{12} units.

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