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photoshop1234 [79]
3 years ago
5

Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = (x − a)(x − b). Describe

the direction of the parabola and determine the y-intercept and zeros.
Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

1) The parabola equation faces up

2) The y-intercept = a·b

3) The zeros are x = a and x = b

Step-by-step explanation:

1) The given information are;

f(x) = (x - a)·(x - b) which gives;

f(x) = x² - (b+a)·x + a·b

For an equation of the form a·x² - b·x + c, if a is positive, then the parabola faces up, therefore, the parabola equation, x² - (b+a)·x + ab where a is equivalent to +1 faces up

2) The y-intercept is given at x = 0, which gives;

f(0) = 0² - (b+a)·0 + a·b

The y-intercept = a·b

3) From f(x) = (x - a)·(x - b), when f(x) = 0, we have either;

(x - a) = 0 or (x - b) = 0

Therefore;

The zeros are x = a and x = b

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Three more than the product of 3 and a number is less than 18
aleksklad [387]

Answer:

x < 5

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3 years ago
A circle passes through (3,-1),(-2, 4), and (6,8)
Vaselesa [24]

Answer:

D = -6, E = -8 , F = 0

Step-by-step explanation:

standard form = x^{2} + y^{2} + Dx + Ey + F = 0

now, when circle passes through (3,-1);

⇒ 3^{2} + (-1)^{2} + D(3) + E(-1) + F = 0

⇒ 3D - E + F + 10 = 0    ...............( equation 1)

when circle passes through (-2,4);

⇒ (-2)^{2} + 4^{2} + D(-2) + E(4)+ F = 0

⇒ -2D + 4E + F + 20 = 0    ...............( equation 2)

when circle passes through (6,8);

⇒ 6^{2} + 8^{2} + D(6) + E(8) + F = 0

⇒ 6D + 8E + F + 100= 0       ................( equation 3)

by solving these 3 equations , we get;

D = -6, E = -8, F = 0

hence,

standard form = x^{2} + y^{2} + Dx + Ey + F = 0

                        = x^{2} + y^{2} - 6x - 8y = 0

5 0
3 years ago
Which expressions are equivalent to 2 (three-fourths x 7) minus 3 (one-half x minus 5)? Check all that apply. -1 29 2 (three-fou
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The expression is equivalent to \rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\.

<h2 /><h2>Given that</h2>

Expression; \rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)

<h3>We have to determine</h3>

Which expressions are equivalent to the given expression.

<h3>According to the question</h3>

Expression; \rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)

To solve the given expression follow all the steps given below.

By applying the distributive property of multiplication;

\rm a(b+c) = ab+ac

Then,

The equivalent expression is,

\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\\&#10;\\&#10;\rm (2 \times \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\&#10;\\&#10;2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\

Hence, the expression is equivalent to \rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\.

To know more about Equation click the link given below.

brainly.com/question/13174611

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