Step-by-step explanation:
x2 - x - 6 = 0
x2 - 3x + 2x - 6 = 0
x(x - 3) + 2(x - 3) = 0
x - 3 = 0. x + 2 = 0
x = 3 x = - 2
Option no 2 and 5 are the correct answer
If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
60.
Multiply
3 by 20.
You can do this on paper,
20
x
3
____
60
Multiply the ones spot first, 0 x 3 is 0 so add that in your ones spot, then go 2x3 since nothing is under to, just go to 3 and you’ll get 6, which you add to the tens spot.
Have a good day!
You need 19 because the median would be the middle of 17 and 19 which would be 18
An algebraic expression consists of one or more numbers and variables, for 1/8y it will be y+1/8
