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mel-nik [20]
3 years ago
9

Ryan wants to prepare for a mini marathon by jogging 12 miles each week. How many days would he need to jog if he runs only 3 mi

les each day? Explain.
Mathematics
1 answer:
DaniilM [7]3 years ago
6 0
Only 4 days because you can just divide 12/3 to get your answer
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Calculate the volume of the figure.
Margarita [4]

Answer:

Step-by-step explanation:

Formula

Volume = L * w * h

Givens

L = 7 feet

w = 4 feet

h = 5 feet

Solution

V = L * w * h             Substitute values into the formula

V = 7 * 4 * 5

V = 140 cubic feet.

Answer

140 ft^3

8 0
2 years ago
Read 2 more answers
Researchers randomly surveyed people at two amusement parks, Funland and Thrillville, to find out how many times they visit the
STALIN [3.7K]

On average, people visit Thrillville 2 more times per year than Funland.

<h3><u>Averages</u></h3>

To determine how many more times per year, on average, do people visit Thrillville than Funland, the following calculation must be performed:

  • Funland: 4,1,2,1,5,6,3,2,4,3,2,6,1,3,2 = 45
  • 45 / 15 = 3
  • Thrillville: 8,6,5,7,2,5,4,2,1,9,3,8,3,7,5,2,9,4,2,8 = 100
  • 100 / 20 = 5
  • 5 - 3 = 2

Therefore, on average, people visit Thrillville 2 more times per year than Funland.

Learn more about averages in brainly.com/question/2426692

4 0
2 years ago
Khan khan khan khan
Ber [7]

Answer:

11

Step-by-step explanation:

it says motor cycles combined with garbage so add both of them then subtract that from the bull dosers

motor =18

garbage=4

18+4=22

bulldosers=11

22-11= 11 more

5 0
3 years ago
Read 2 more answers
What is the enlargement ratio if you enlarge the figure to have a width of 16 units and length of 12 units
Fantom [35]

Answer:

The enlargement ratio is 3:4

Step-by-step explanation:

We are given

a width of 16 units and length of 12 units

so,

W=16

and

L=12

now, we can find enlargement ratio

we can use formula

enlargement ratio = (length)/(width)

=\frac{L}{W}

now, we can plug values

=\frac{12}{16}

now, we can simplify it

=\frac{3}{4}

So,

The enlargement ratio is 3:4

6 0
3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 5​% will need repairs​
gtnhenbr [62]

Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

<u>a) Neither will need repair:</u>

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

<u>b) Both will need repair:</u>

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

<u>c) At least one car will need repair</u>

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74)  = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

4 0
3 years ago
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