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Anna35 [415]
3 years ago
5

1.Simplify 5 to the 5th over 5 to the 8th.

Mathematics
2 answers:
disa [49]3 years ago
7 0

Answer:

it is (A) 1 over 5 to the 3rd power

Step-by-step explanation:

timurjin [86]3 years ago
3 0
Q1. The answer is <span>1 over 5 to the 3rd power.

</span>5 to the 5th is 5⁵
5 to the 8th is 5⁸
5 to the 5th over 5 to the 8th is \frac{ 5^{5} }{ 5^{8} }
To simplify, we will use two rules: 
\frac{ x^{a}}{ x^{b} } = x^{a-b} \\ x^{-a} = \frac{1}{ x^{a}}
Therefore:
\frac{ 5^{5} }{ 5^{8} } = 5^{5-8} =5^{-3}= \frac{1}{5^{3}}
\frac{1}{5^{3}} is the same as 1 over 5 to the 3rd power.


Q2. The answer is <span>(53)−4.

The exponents are multiplied when are expressed in the form:
</span>(x^{a}) ^{b}= x^{a*b}
So, (5^{3} )^{-4}=5^{3*(-4)}=5^{-12}

Other choices are incorrect:
<span>one third to the 4th times one third to the 7th is </span>( \frac{1}{3} )^{4} *( \frac{1}{3} )^{7}=( \frac{1}{3} )^{4+7}
3 to the 7th over 3 to the 15th is \frac{ 3^{7} }{3^{15}} =3^{7-15}
<span>45 ⋅ 42 is </span>4^{5}* 4^{2} =  4^{5+2}
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Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =
dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

5x2 + 26x - 320 = 0

Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27­°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

8 0
4 years ago
When three times the sum of a number and seven is increased by ten, the result is four. What is the number ?
densk [106]

Answer:

x=9   :))

Step-by-step explanation:

First set up your equation.

"3 times" is multiplication

"THE SUM of A NUMBER and seven" that is parenthesis because of the multiplication before it

"is increased by ten" that is an addition at the end

Now we have 3(x+7)+10=4

Solve your equation!

Distribute the 3 now we have 3x+21+10=4

Add like terms

now it should look like this... 3x+31=4

Subtract 31 from both sides and it looks like...

3x=27

Divide by the x-value

x=9

4 0
4 years ago
How do i do this?....... ​
iris [78.8K]

Order of operations (from high priority to low priority):

Parentheses

Exponents

Multiplications/Division

Addition/Subtraction

All in left to right.

2 ÷ (5 + 3)⁻¹ ÷ 4

2 ÷ (8)⁻¹ ÷ 4

2 ÷ 1/8 ÷ 4

16 ÷ 4

= 4

3 0
3 years ago
Read 2 more answers
A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
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