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3 years ago

Does a triangle with these side lengths exist? 28, 41, 13

Mathematics

2 answers:

Reika [66]3 years ago

8 0

Answer:

Step-by-step explanation:

it doesnt add up to 180 degrees

pychu [463]3 years ago

6 0

Use the triangle inequality theorem.

Add two sides together and see if it is greater than the length of the 3rd side:

28 + 41 = 69 which is greater than 13

41 + 13 = 54 which is greater than 28

28 + 13 = 41 this is equal to the 3rd side length of 41 and not greater than 41

Because 28 + 13 is not greater than 41 those 3 lengths cannot make a triangle.

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Rus_ich [418]

None of the were negative

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4 years ago

The position, x, of an object is given by the equation x = A + Bt +Ct2, where t refers to time. What are the dimensions of A, B,

Serjik [45]

Answer: Dimensions of A are of length [L]

Dimensions of B are of $LT^{-1}$

Dimensions of C are of $LT^{-2}$

Step-by-step explanation:

The given equation is

$x(t)=A+Bt+Ct^{2}$

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid

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$Bt=[L]\\\\$ $[B][T]=[L]$ $\\\\\therefore [B]=LT^{-1}$

Similarly

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3 years ago

X= 5y + 7 2x + 4y = 0 Solve for substitution

algol13

Answer:

x=2 and y= -1

Step-by-step explanation:

substitute x value in equation 2

2(5y+7)+4y=0

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14y = -14

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here,

x= 5(-1)+7

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Answer:

Step-by-step explanation:

GCF(18, a, 20ab) = 1

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