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Mariana [72]
3 years ago
11

A recent survey in Montana revealed that 20% of the vehicles traveling on highways, where speed limits are posted at 70 miles pe

r hour, were exceeding the limit. Suppose you randomly record the speeds of ten vehicles traveling on US 131 where the speed limit is 70 miles per hour. Let X denote the number of vehicles that were exceeding the limit. What is the probability that exactly 3 vehicles were exceeding the limit?
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0
This is a binomial problem. Binompdf(10,0.2,3)=0.201, about 20% chance
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Math Questions :3 thank uu <3
coldgirl [10]
14.       1.5, 10    <- Answer
15.       5,1          <- Answer

Proof 14 

Solve the following system:
{2 x - y = -7 | (equation 1)
4 x - y = -4 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -4 | (equation 1)
2 x - y = -7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{4 x - y = -4 | (equation 1)
0 x - y/2 = -5 | (equation 2)
Multiply equation 2 by -2:
{4 x - y = -4 | (equation 1)
0 x+y = 10 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = 6 | (equation 1)
0 x+y = 10 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3/2 | (equation 1)
0 x+y = 10 | (equation 2)
Collect results:
Answer: {x = 1.5               
                y = 10

Proof 15. 

Solve the following system:
{5 x + 7 y = 32 | (equation 1)
8 x + 6 y = 46 | (equation 2)
Swap equation 1 with equation 2:
{8 x + 6 y = 46 | (equation 1)
5 x + 7 y = 32 | (equation 2)
Subtract 5/8 × (equation 1) from equation 2:{8 x + 6 y = 46 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 23 | (equation 1)
0 x+(13 y)/4 = 13/4 | (equation 2)
Multiply equation 2 by 4/13:
{4 x + 3 y = 23 | (equation 1)
0 x+y = 1 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 20 | (equation 1)
0 x+y = 1 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 5 | (equation 1)
0 x+y = 1 | (equation 2)
Collect results:
Answer:  {x = 5                           y = 1
8 0
3 years ago
Subtract (–x – 2) – (4x + 3).
Alekssandra [29.7K]
The first set of parentheses is unnecessary, so just drop it.
The second set of parentheses has a negative sign to its left.
To simplify the second set of parentheses, change every sign inside the parentheses. Then combine like terms.

<span>(–x – 2) – (4x + 3) =

= - x - 2 - 4x - 3

= -x - 4x - 2 - 3

= -5x - 5
</span>
7 0
3 years ago
Are these answers right or some wrong? If some wrong plz answer them correct thanks!
maxonik [38]

You are wrong.

1, 2, 3 and 4 are correct.

5. 75%

6 is also correct

7. 100%

8. 50%

7 0
3 years ago
Read 2 more answers
Question 18: please help. I will give brainliest to correct answer.
Veronika [31]

Answer:

3. mean of 2nd is larger

Step-by-step explanation:

mean of 2nd sem 87 > 86.8 1st sem

7 0
4 years ago
Read 2 more answers
George sold 18, 22, 26, 12, 25, 20, and 19 cars per month over the past seven months. He followed the steps below to determine t
Crazy boy [7]
<h2>Hello!</h2>

The answer is: George made his first mistake in Step 1.

<h2>Why?</h2>

Getting a result of 26 cars needed means that he didn't take in consideration the next month in the mean calculation.

We have information of the number of sold cars of the first seven months, but if he wants to calculate the number of cards he needs to have a mean of 24 sold cards next months, he should take in consideration an extra month (the eighth month).

Checking the mistake:

\frac{18 + 22 + 26 +12 + 25 +20 + 19 + x }{7}=24

\frac{18 + 22 + 26 +12 + 25 +20 + 19 + x }{7}=24\\x=26

So, it proves that he made a mistake by multiplying it into 7 and instead into 8

The correct answer would be:

\frac{18 + 22 + 26 +12 + 25 +20 + 19 + x }{8}=24\\x=50

He needed to include the eighth month in order to calculate how many cars he should sell next months in order to have a mean of 24 cars.

Have a nice day!

3 0
3 years ago
Read 2 more answers
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