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MaRussiya [10]
3 years ago
11

Please help!! MATH | WILL MARK BRAINLIEST!! 40 POINTS

Mathematics
1 answer:
madreJ [45]3 years ago
3 0

Answer:

y = 9 cos [(⅕pi)x]

Step-by-step explanation:

Amplitude = 9

Period = 10

2pi/10 = pi/5

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Complete the Table
lianna [129]

Answer:

a= 6

b = 7

c = 8

d = 7

e = 6

Step-by-step explanation:

Notice that the bike is 6 feet above the ground to start with, so when it starts rolling, the green dot is exactly 6 feet from the ground, which gives a=6

when the distance covered by the bike is \frac{\pi}{2}, (see first red dot in the attached image), the position of the green dot is exactly 1 foot added to 6 ft= 7 feet

so b = 7

when the distance covered is \pi, now the green dot would be at the top of the wheel (second red dot in the attached image) which involves adding 2 feet to the original 6 feet. That is: c = 8

when the distance covered is \frac{3\pi}{2}, the green dot is at the position of the third red dot in the attached image., that it exactly one foot added to 6 feet = 7 ft which gives the value of d = 7

and finally, when the distance covered is 2\pi. the green dot has completed a full circle and is now again in its lower position (nothing - zero) added to 6 feet =  6ft, giving e = 6.

5 0
3 years ago
Help as quick and i will give the brainliest!!!
Arte-miy333 [17]

I believe both answers are Shannon.

3 0
2 years ago
Read 2 more answers
Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt
polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt

=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k

The first integral is trivial since (\tan t)'=\sec^2t.

The second can be done by substituting u=t^2-1:

u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C

The third can be found by integrating by parts:

u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t

\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8

\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C

8 0
3 years ago
HELP PLEASE!<br> Solve for m.<br><br> 3.6m = 14.4
Alekssandra [29.7K]

Answer:

4m

Step-by-step explanation:

5 0
2 years ago
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crackers come in packages of 24 cheese slices come in packages of 18 andy wants one cheese slice for each cracker
Ksivusya [100]
If you were asking for how many packages you would like if each you would want one pack of crackers, and two packages of cheese. Simple math. The reason why you get that answer and that equation/solution, is by simply make ing the cheese grater then the crackers, but if the cheese is lower then the crackers, you get more cheese packages because then you get two times the cheese and you will have enough cheese for all the crackers. You may have a little bit of cheese left, but who doesn't like it plain? That is the answer.
3 0
3 years ago
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