C' ( 0, 3)
A' ( 2 , 1)
C'A' = CA
C'A' = √(2^2 + 2^2) = √8 = 2√2
C'A' = CA = 2√2
I would but my teacher has a ad blocker on and I cant access the attachment :P
Pick any point and then plug the domain and range into x (domain value) and y (range value).
10/12 that should be a correct answer :)
Answer:
2x^3+6x^2-4x-12
Step-by-step explanation:
