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Arada [10]
3 years ago
7

Write an equation of the parabola that opens up whose vertex (−1, 2) is 3 units from the focus. (Vertex form or Parabola Form is

acceptable) PLZZ HELP ASAP!!!!!!!!!!!
Mathematics
1 answer:
TEA [102]3 years ago
7 0

Answer:

y2  =  4ax (opens right, a > 0)

y2  =  -4ax (opens right, a > 0)

x2  =  4ay (opens up, a > 0)

x2  =  -4ay (opens down, a > 0)

Vertex at (h, k) :  

(y - k)2  =  4a(x - h) (opens right, a > 0)

(y - k)2  =  -4a(x - h) (opens right, a > 0)

(x - h)2  =  4a(y - k) (opens up, a > 0)

(x - h)2  =  -4a(y - k) (opens down, a > 0)

Equation of a Parabola in Vertex form

Vertex at Origin :  

y  =  ax2 (opens up, a > 0)

y  =  -ax2 (opens down, a > 0)

x  =  ay2 (opens right, a > 0)

x  =  -ay2 (opens left, a > 0)

Vertex at (h, k) :  

y  =  a(x - h)2 + k (opens up, a > 0)

y  =  -a(x - h)2 + k (opens down, a > 0)

x  =  a(y - k)2 + h (opens right, a > 0)

y  =  -a(y - k)2 + h (opens left, a > 0)

Step-by-step explanation:

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5 0
3 years ago
Solve by elimination <br> -5x+8y=-27<br> -8x+7y=-20
Anika [276]

Answer:

x = -1 , y = -4

Step-by-step explanation by elimination:

Solve the following system:

{8 y - 5 x = -27 | (equation 1)

7 y - 8 x = -20 | (equation 2)

Swap equation 1 with equation 2:

{-(8 x) + 7 y = -20 | (equation 1)

-(5 x) + 8 y = -27 | (equation 2)

Subtract 5/8 × (equation 1) from equation 2:

{-(8 x) + 7 y = -20 | (equation 1)

0 x+(29 y)/8 = (-29)/2 | (equation 2)

Multiply equation 2 by 8/29:

{-(8 x) + 7 y = -20 | (equation 1)

0 x+y = -4 | (equation 2)

Subtract 7 × (equation 2) from equation 1:

{-(8 x)+0 y = 8 | (equation 1)

0 x+y = -4 | (equation 2)

Divide equation 1 by -8:

{x+0 y = -1 | (equation 1)

0 x+y = -4 | (equation 2)

Collect results:

Answer:  {x = -1 , y = -4

7 0
3 years ago
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