First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps<span />
Answer:
26%
Step-by-step explanation:
Your 36 monthly payments will total ...
36 × $205.10 = $7383.60
$5860 of that is the amount you borrowed. The remainder is the interest you pay:
$7383.60 -5860 = $1,523.60
As a percentage of the original loan amount this is ...
$1523.60/$5860 × 100% = 26%
You pay back 26% of the original loan amount in interest.
1. N + 2; n = 6: the answer is 8 because n=6 so we sub n with that... and we get 6+2 and that’s 8.
2.5f; where f=4: the answer is 20 because when a variable is directly next to a number it is multiplied by that number so we will replace f with 4 and our equation is now 5(4) or 5•4 and both are equivalent to 20.
3. 7b-2; where b=5: the answer is 33 because 7 multiplied by 5(b) minus 2= 7(5)-2 or 7•5-2= 33 because you will multiply 7 by 5 and get 33 then you will subtract by 2 and get 33.
Hope this helps!!!
Step-by-step explanation:
- In the first parabola it opens on the left and the equation of parabola can be expressed as,
in vertical component <u>(y)² = (-) a (x-h)² + k</u>
cause the parabola is horizontal and it opens on the left.
2. In the second parabola the vertex opens on the right and hence the equation cane be given as,
in vertical component <u>(y)² = a (x-h)² + k</u>
cause the parabola is horizontal and opens on the right.
3. the third equation is given as,
in horizontal component<u> (x²) =</u> <u> (-) a (x-h)² + k</u>
since the parabola is vertical and opens down.
4. the fourth equation is given as,
in the horizontal component <u>(x)² = a (x-h)² + k</u>
since the parabola is vertical and opens up.