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elena55 [62]
3 years ago
9

What is 0.0000034 written in scientific notation?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
I believe the answer is 34x10^-6
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What is the solution of the equation 70 = 1.4y ?
sdas [7]
So you basically have to divide 1.4 on both sides so you can get y by its self. Once you divide 60 by 1.4 you’ll get 50.

y=50
7 0
3 years ago
I WILL UPVOTE YOUR ANSWER!!<br> ANSWER THIS CORRCTLY<br> THANK YOU!
kramer
-0.85, 0.25, 60, 60 2/40
hope this helps! :)
8 0
3 years ago
Please help me with this homework
3241004551 [841]

Answer:

C.

Step-by-step explanation:

The pythagorean theorem shows a^2+b^2=c^2.

a=8, b=15, c= the unknown distance

8^2+15^2=c^2

7 0
3 years ago
What is 7 and 1/5 written as a percent?
Gennadij [26K]

7 \frac{1}{5}
equivalent to

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5 0
3 years ago
Read 2 more answers
A flashlight battery manufacturer makes a model of battery whose mean shelf life is three years and four months, with a standard
Vladimir [108]

Answer:

17,065 of those batteries can be expected to last between three years and one month and three years and seven months

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem:

I will calculate the time in months. Each year has twelve months.

Mean shelf life is three years and four months, with a standard deviation of three months. So

\mu = 3*12 + 4 = 40

\sigma = 3

Proportion lasting between three years and one month and three years and seven months:

This is the pvalue of Z when X = 3*12 + 7 = 43 subtracted by the pvalue of Z when X = 3*12 + 1 = 37

X = 43

Z = \frac{X - \mu}{\sigma}

Z = \frac{43 - 40}{3}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 37

Z = \frac{X - \mu}{\sigma}

Z = \frac{37 - 40}{3}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.8413 - 0.1587 = 0.6826

Out of 25,000 batteries:

68.26% of the batteries are expected to last between three years and one month and three years and seven months.

0.6826*25000 = 17,065

17,065 of those batteries can be expected to last between three years and one month and three years and seven months

6 0
3 years ago
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