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Oliga [24]
3 years ago
13

the cost to rent a photo booth for a party is a one time fee of $25 plus $30 per hour the photo booth is running. If the photo b

ooth cost a total of $180. Which equation could be used to find the number of hours, h, the photo booth was running?
Mathematics
1 answer:
sdas [7]3 years ago
6 0

Answer: 25+30h=180

Step-by-step explanation:

The one time fee is 25 and plus the $30 per hour so you have 25 plus $30 h= hour equals 180. I took the a test and got it right btw.

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The cafeteria uses rectangular trays with a raised edge around them. The area of the flat surface of each tray is 228 Inches squ
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PLSS HELP ME FIND THE SURFACE AREA OF THE TRIANGULAR PRISM <br><br> THXXSSSS AND HURRY PLS
aleksley [76]

Answer:

108m^2

Step-by-step explanation:

surface area of any shape: sum of the area of its sides.

area of cross section x 2 = 4 x 3 12 m^2

area of slope:  5m x 8m = 40m^2

area of base: 8 X 3 = 24 m^2

area of back: 8m x 4m = 32m^2

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Ethan has 31 presents Alissa has 22 more than Ethan how many presents does Alissa have
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Alissa has 53 presents
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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
Andrei [34K]

Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

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