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Oliga [24]
3 years ago
13

the cost to rent a photo booth for a party is a one time fee of $25 plus $30 per hour the photo booth is running. If the photo b

ooth cost a total of $180. Which equation could be used to find the number of hours, h, the photo booth was running?
Mathematics
1 answer:
sdas [7]3 years ago
6 0

Answer: 25+30h=180

Step-by-step explanation:

The one time fee is 25 and plus the $30 per hour so you have 25 plus $30 h= hour equals 180. I took the a test and got it right btw.

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Conditions of a triangle = AAA
34kurt

Answer:

One triangle

Step-by-step explanation:

That's the answer....

3 0
2 years ago
1. The zeros of a quadratic relation are 3 and The second differences are positive
nata0808 [166]

Answer:

The optimal, vertex, value will be a minimum

Step-by-step explanation:

The given zeros of the quadratic relation are 3 and 3

The sign of the second differences of the quadratic relation = Positive

Whereby the two zeros are the same as x = 3, we have that the point 3 is the optimal value or vertex (the repeated point in the graph of the quadratic relation) of the quadratic relation

Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;

To the right of the coordinate points of the zeros of the quadratic relation, the positive second difference in y-values gives as x increases, y increases which gives a positive slope

By the nature of the quadratic graph, the slope of the line to the left of the coordinate point of the zeros of the quadratic relation will be of opposite sign (or negative). The quadratic relation is cup shaped and the zeros, therefore, the optimal value will be a minimum of the quadratic relation

8 0
2 years ago
What is the slope of the line through (1,-1)(1,−1)left parenthesis, 1, comma, minus, 1, right parenthesis and (5,-7)(5,−7)left p
Leona [35]

Answer:

-3/2

Step-by-step explanation:

We can find the slope between two points using

m = (y2-y1)/(x2-x1)

  = (-7 - -1)/(5 - 1)

  (-7+1(/(5-1)

  -6/4

  -3/2

5 0
3 years ago
What else would need to be congruent to show that jkl mno by aas
vredina [299]
AAS<span> is equal to angle-angle-side, and is descriptive of a triangle. </span>JKL and MNO would be the sides and angles of a triangle. The two sides must be congruent. I hope my answer has come to your help. God bless and have a nice day ahead! Feel free to ask more questions.
4 0
3 years ago
Helppppp!!! I don’t know what the answer is and I’m taking the test right now....
Darya [45]

Answer:

<h2>x =  - 4± \sqrt{2}</h2>

Step-by-step explanation:

Hint :

  • \frac{−b± \sqrt{{b}^{2} −4(ac} )}{2a}

Simplify :

{x}^{2} +8x+16=2

{x}^{2} +8x+16−2=0

{x}^{2} +8x+14=0

<h3>\frac{ - 8± \sqrt{ {8}^{2} - 4(1 \times 14) } }{2 \times 1}</h3><h3>x =  \frac{ - 8±2 \sqrt{2} }{2 \times 1}</h3><h3>x = \frac{- 8±2 \sqrt{2}}{2}</h3>

x =  - 4± \sqrt{2}

<h3>Hope it is helpful....</h3>
4 0
3 years ago
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