1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
forsale [732]
3 years ago
12

how tall are sally and anna if sally is 0.1m taller than anna and their combined height is 3.16 meters

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0
Set up a simple equation with S FOR SALLY AND A FOR ANNA LOOKS LIKE THIS A+(A+.1)=3.16
nordsb [41]3 years ago
3 0
Anna = a
sally = 0.1 + a
a + s = 3.16
a + 0.1 + a = 3.16
2a = 3.16 - 0.1
2a = 3.06
a = 1.53
s = 0.1 + 1.53
s = 1.63<span />
You might be interested in
20 POINTS!!!!!
Rom4ik [11]

Answer:

5/the number of socks he has

8 0
2 years ago
Mark's coach told him that he should
Georgia [21]

Answer:

24 practices in 9 weeks

Step-by-step explanation:

Rate =   8 times / 3 weeks

8 times / 3 weeks    *   9 weeks  = 24 times

5 0
1 year ago
Identify any outliers of the data set. Then determine the effect that the outlier has on the mean. 25, 29, 58, 27, 23, 26, 27, 2
Murrr4er [49]

Answer:

58

Step-by-step explanation:

58 would increase the mean since it is much higher than the other numbers, making the data inaccurate

7 0
3 years ago
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
2 years ago
What is 0.05 divided by 4.8 ?
postnew [5]
I Got 0.01041666666 As An Answer <span />
5 0
3 years ago
Read 2 more answers
Other questions:
  • What is the next fraction in this sequence? Simplify your answer. 3/4, 1/4, 1/12, 1/36
    12·1 answer
  • How do you find the derivative of f(x)=cos(x)f(x)=cos(x) ?
    8·1 answer
  • Please asap help im desperate.......................
    5·1 answer
  • Bonnie planted a garden in her backyard. Both the garden and the backyard are right triangles. The garden is proportional to the
    11·1 answer
  • Determine whether or not the triangles below or similar
    5·1 answer
  • For the data shown in the scatter plot, which is the best estimate of r?
    10·1 answer
  • The Eurasian tectonic plate travels at a
    12·1 answer
  • Please please help and explain! I will mark Brainliest.
    12·2 answers
  • What number has a prime factorization of 2x 5^2
    5·2 answers
  • If f(x)=8x^2-1 then what is f(2)<br> Show work
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!