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3 years ago

PLZZZZZZZZZ HELP 7x + 10 + -2 + -2 =

Mathematics

2 answers:

Naddik [55]3 years ago

7 0

Answer:

The answer is 13x

Step-by-step explanation:

PSYCHO15rus [73]3 years ago

6 0

Answer:

Unsolvable

Step-by-step explanation:

If you're looking for the value of x, that equal sign would have to be somewhere in the equation. It can't be in at the end or beginning. If you fix that, I can help you solve it.

-Kate

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Westkost [7]

Answer:

Circumference = πd

where d = diameter

Step-by-step explanation:

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According to the fundamental theorem of algebra, how many zeros does the function f(x) = 15x17 + 41x12 + 13x3 − 10 have?

liberstina [14]

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Simplify: 5j - (2j - 6). Thanks!

xxMikexx [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Substitute the value in for the variable. Then solve. Remember your order of operations!

inna [77]

Answer:

Step-by-step explanation:

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2 years ago

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compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago