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Margarita [4]
3 years ago
10

I really need help they never taught me this in my old school.

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
6 0
To find this, just plug the numbers into the expressions.

5x = y
5(2) = 7
10 = 7
So it can't be A.

x + 2 = y
2 + 2 = 7
4 = 7

x + 4 = y
2 + 4 = 7
6 = 7

2x + 3 = y
2(2) + 3 = 7
7 = 7

The correct answer is
D. 2x + 3
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What is 4<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="late
Alisiya [41]

Answer:

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
11 more than four times a number is 39
Aliun [14]

Hello!

Your answer is: 7

(X = "<em>A number</em>")

<em>"11 more than four times a number is 39"</em> in equation form is: 4X + 11 = 39

to solve, first subtract 11 from both sides:

4X = 28

then divide both sides by 4 to get:

X = 7

I hope this helps, and have a nice day!

4 0
3 years ago
1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
2 years ago
How many divisors of 63 are also divisors of 72? (Recall that divisors may be positive or negative.)
frutty [35]

1, 3, 9 and -1, -3, and -9 i guess

hope this helps

8 0
3 years ago
20 Points + Brainliest for the answer and Explanation!!!
Vlad1618 [11]

Answer:

P+Q=5x^2+4

Q-P=-x^2-4x+16

Step-by-step explanation:

We are given

P=3x^2+2x-6

Q=2x^2-2x+10

Calculation of P+Q:

P+Q=3x^2+2x-6+2x^2-2x+10

now, we can combine like terms

P+Q=3x^2+2x^2+2x-2x+10-6

P+Q=5x^2+0+4

P+Q=5x^2+4

Calculation of Q-P:

Q-P=2x^2-2x+10-(3x^2+2x-6)

Firstly, we will distribute negative sign

Q-P=2x^2-2x+10-3x^2-2x+6

now, we can combine like terms

Q-P=2x^2-3x^2-2x-2x+6+10

Q-P=-x^2-4x+16

8 0
2 years ago
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