All categories

3 years ago

I really need help they never taught me this in my old school.

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

6 0

To find this, just plug the numbers into the expressions.

5x = y
5(2) = 7
10 = 7
So it can't be A.

x + 2 = y
2 + 2 = 7
4 = 7

x + 4 = y
2 + 4 = 7
6 = 7

2x + 3 = y
2(2) + 3 = 7
7 = 7

The correct answer is
D. 2x + 3

You might be interested in

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam, which of the following is the number of senior

dalvyx [7]

Answer:

The number of seniors who scored above 96% is 1.

Step-by-step explanation:

Consider the provided information.

Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.

Now we need to find the number of seniors who scored above 96%

For this we need to find the two percent of 50.

2% of 50 can be calculated as:

$\frac{2}{100}\times50$

$\frac{100}{100}$

$1$

Hence, the number of seniors who scored above 96% is 1.

6 0

3 years ago

Pls help I need help plsss

Mkey [24]

Answer:

C, D, E

Step-by-step explanation:

≥ means that x is either more than or equal to 15. The numbers that fit this are 15, 24, and 32.

Please give brainliest if I helped! :)

4 0

2 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago

Which of the following is a solution to the inequality?

Liono4ka [1.6K]

Answer:

M= 25

<h2>step by step Explanation:</h2>

i think this is correct ans if this is correct ans pls give me brainliest.

3 0

3 years ago

Find Y ...............................

Arisa [49]

36/24= y/20

3/2 = y/20

(3/2) × 20 = y

3 × 10 = y

30 = y

3 0

3 years ago