P is the point (2,k)
PA = PB
PA = √(49 + (2-k)²) and PB = √(1 + (6 - k)²)
√(49 + (2-k)²) = √(1 + (6 - k)²) => (49 + (2-k)² = (1 + (6 - k)²
=> 49 + 4 - 4k + k² = 1 + 36 - 12k + k² => 8k = 37 - 53 = -16 => k = -2
K= 52!!
hoped this helped .
The question is incomplete. Here is the complete question:
Mr.yueng graded his students math quizzes students came up with four different answers when solving the equation x3=22. Which answers is correct.
(A) 
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D%20)
(C)
(D) 
Answer:
(B) ![\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B22%7D)
Step-by-step explanation:
Given:
The equation to solve is given as:

Here, the left hand side of the equation has a variable 'x' in exponent form. So, in order to solve for 'x', we have to eliminate the exponent.
For removing the exponent, we have to take cubic root on both the sides. As we know that,
![\sqrt[n]{x^n} =x](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D%20%3Dx)
So, taking cubic root on both the sides, we get
![\sqrt[3]{x^3}=\sqrt[3]{22}\\\\x=\sqrt[3]{22}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%3D%5Csqrt%5B3%5D%7B22%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B22%7D)
Therefore, the second student has written the correct answer and hence the correct option is (B).
The formula to find the arc length L is
L = r*theta
where r is the radius and theta is the central angle in radians (this formula will not work if theta is in degrees)
If the central angle is 1 radian, then theta = 1 and
L = r*theta
L = r*1
L = r
So the arc length is the same as the radius
Answer: Choice A) The radius of the circle
The discount rate is 60%. Hope this helps.