Answer:
93/100
Step-by-step explanation:
Monthly Payment $308.59
Total Principal Paid $21,621Total Interest Paid <span>$597.13</span>
At the end of the zeroth year, the population is 200.
At the end of the first year, the population is 200(0.96)¹
At the end of the second year, the population is 200(0.96)²
We can generalise this to become at the end of the nth year as 200(0.96)ⁿ
Now, we need to know when the population will be less than 170.
So, 170 ≤ 200(0.96)ⁿ
170/200 ≤ 0.96ⁿ
17/20 ≤ 0.96ⁿ
Let 17/20 = 0.96ⁿ, first.
log_0.96(17/2) = n
n = ln(17/20)/ln(0.96)
n will be the 4th year, as after the third year, the population reaches ≈176
For ex:
U have 4/8 - 6/2 u would probably have to use KCF- Keep Change Flip
So then it’ll be 4/8 + 2/6
U kept the 4/8 then u changed the subtraction to addition and u flipped the 2 to the numerator and the 6 denominator.
Idk my dude this is what I can think of
Answer:
x= 3
Step-by-step explanation:
