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Leviafan [203]
3 years ago
13

Which equation with exponential expression are true?

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:B and E

It is B and E because it’s exponent matches the equation. In B, there are 2 fives and the exponential form shows 5 to the power of 2. In E, there are 6 sevens and the exponential form shows 7 to the power of 6.

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There is a bag with only red marbles and blue marbles.
Genrish500 [490]

Answer:

49 red marbles

Step-by-step explanation:

We should first make 5/12 have a base of 84, so that'll be

(5*7)/(12*7)=35/84. So we have 35 blue marbles and all the rest are red, so 84-35=49

DUBS

Please consider giving me a brainliest! Thank you.

7 0
3 years ago
7-5p+3q when p=1 and q=7
Mnenie [13.5K]

Answer:

23

Step-by-step explanation:

7 - 5p + 3q

p = 1, q = 7

Substitute in the values of "p" and "q", and solve;

7 - 5(1) + 3(7)

7 - 5 + 21

2 + 21

23

5 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Using the formula y=ab/2c, express: the variable c in terms of a, b, and y.
adelina 88 [10]

Answer:

aby/2 = c

Step-by-step explanation:

1) ab * y = ab/2c

2) aby/2 = 2c/2

Final answer: aby/2 = c

4 0
3 years ago
If Sarah turns 15 on august 27 and her graduation year is 2024 how old will she be when she graduates high school?
mart [117]

Answer:

She will be 17

Step-by-step explanation:

My sister is like that but she's graduating in 22'

4 0
3 years ago
Read 2 more answers
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