That can also be written as 1/6y^5
Answer:16
Step-by-step explanation:
Let the number be X
Twice the sum of a number and 5
= 2X+5
Three times the difference of the number and 2
= 3(X - 2)
Since Twice the sum of X and 5 is equal to three times the difference of the X and 2, This means
2(X + 5 )= 3(X - 2)
2X +10 = 3X - 6
3X -2X = 10 + 6 = 16
X = 16
Check
2×(16+5) =3×(16-2)
2×21 = 3×14
42 = 42
So what we have to do to solve this problem is to write down those values in 2 equations (one that represents what you sold and the other what your friend sold) compare them and find how much each ticket is worth.
First equation : 11x + 8y = 158
Where x = how much each adult ticket is
and y = how much each student ticket is
The second equation is : 5x + 17y = 152
Using the method of substitution , we can compare each equation side by side:
11x + 8y = 158
5x + 17y = 152
Now we need to set one of the variables of both equations so they are equal:
11(5)x + 8(5) = 158(5)
5(11)x + 17(11)x = 152(11)
55x + 40y = 790
55x + 187y = 1672
Then we subtract the second equation by the first one
55x-55x + 187y - 40y = 1672 - 790
147y = 882
y = 6
The we apply y to one of the equations to discover x :
11x + 8y = 158
11x + 8(6) = 158
11x + 48 = 158
11x = 110
x = 10
So the awnser is :
Each adult ticket (x) is $10
And each student ticket (y) is $8
I hope you understood my explanation,
