Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
5 units
Step-by-step explanation:
Please see attached pictures for the full solution.
(This distance is the perpendicular distance between the 2 parallel lines, which is the shortest distance between them.)
Answer/Step-by-step explanation:
the fibonacci sequence is {1, 1, 2, 3, 5, 8, 13, 21, 34…} and in the visual for the Golden Ratio, if you look those are the those are the numbers that basically equals the golden ration, 1.618.
Puff trees smash freaks and eat between the cheeks
Answer:
Infinitely many solutions (the lines are identical)
Step-by-step explanation:
Let's start by getting each equation into slope intercept form (y=mx+b)
-14x-14y=28
-14x-28=14y
-x-2=y
and
7x+7y= -14
7x+14= -7y
-x-2=y
We can see that these two lines are identical which means that there are an infinite amount of answers
