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Igoryamba
3 years ago
15

Evaluate the indefinite integral. (use c for the constant of integration.) tan6(θ) sec2(θ) dθ illustrate and check that your ans

wer is reasonable by graphing both the function and its antiderivative (take c = 0). webassign plot webassign plot webassign plot webassign plot
Mathematics
1 answer:
atroni [7]3 years ago
4 0
\displaystyle\int\tan^6\theta\sec^2\theta\,\mathrm d\theta

x=\tan\theta\implies\mathrm dx=\sec^2\theta\,\mathrm d\theta

\displaystyle\int x^6\,\mathrm dx=\dfrac{x^7}7+C
\implies\displaystyle\int\tan^6\theta\sec^2\theta\,\mathrm d\theta=\dfrac{\tan^7\theta}7+C
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Simplify (3^3)(1/9^2 − 6 + 2)
AnnZ [28]

Answer:

27/77

Step-by-step explanation:

I hope this is correct

Have a good Day!

3 0
3 years ago
HELP!!
leonid [27]

Answer:

The focus point is (2 , 0) ⇒ answer D

Step-by-step explanation:

* Lets revise the equation of the parabola in standard form

- The standard form is (x - h)² = 4p(y - k)

- The focus is (h, k + p)

- The directrix is y = k - p

- If the parabola is rotated so that its vertex is (h , k) and its axis of

 symmetry is parallel to the x-axis, it has an equation of

 (y - k)² = 4p(x - h)

- The focus is (h + p, k)

- The directrix is x = h - p

* Lets solve the problem

∵ The equation of the parabola is y = 1/8(x² - 4x - 12)

- Lets make x² - 4x completing square

∵ √x² = x  

∴ The 1st term in the bracket is x

∵ 4x ÷ 2 = 2x

∴ The product of the 1st term and the 2nd term is 2x

∵ The 1st term is x

∴ the second term = 2x ÷ x = 2

∴ The bracket is (x - 2)²

∵  (x - 2)² = (x² - 4x + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out  

  the bracket to keep the equation as it

∴ (x² - 4x + 4) - 4 = (x - 2)² - 4

- Lets put the equation after making the completing square

∴ y = 1/8 [(x - 2)² - 4 - 12]

∴ y = 1/8 [(x - 2)² - 16] ⇒ multiply both sides by 8

∴ 8y = (x - 2)² - 16 ⇒ add 16 to both sides

∴ 8y + 16 = (x - 2)² ⇒ take from the left side 8 as a common factor

∴ 8(y + 2) = (x - 2)²

∴ The standard form of the equation of the parabola is

   (x - 2)² = 8(y + 2)

∵ The standard form of the equation is (x - h)² = 4p(y - k)

∴ h = 2 , k = -2 , 4p = 8

∵ The focus is (h , k + p)

∵ h = 2

∵ 4p = 8 ⇒ divide both sides by 4

∴ p = 2

∴ The focus = (2 , -2 + 2) = (2 , 0)

* The focus point is (2 , 0)

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