9514 1404 393
Answer:
m∠B < m∠A < m∠C
Step-by-step explanation:
We can work with the triangle inequality to find that the side measures form a triangle when n > 5/4. For the given value of n ≥ 4, we don't need to be concerned with whether a triangle is formed or not.
For n = 4, the side lengths are ...
a = 2(4) = 8
b = (4) +3 = 7
c = 3(4) -2 = 10
The longest side is opposite the largest angle, so the ordering of angles is ...
m∠B < m∠A < m∠C
_____
The triangle inequality requires all of these inequalities be true:
- a+b > c ⇒ 3n+3 > 3n-2 . . . always true
- b+c > a ⇒ 4n+1 > 2n ⇒ n > -1/2
- c+a > b ⇒ 5n-2 > n+3 ⇒ n > 5/4
That will be the case for n > 5/4. The attached graph shows the sides and angles keep the same order for n > 3.
How I would do it is place a point at 1 then go up 1 over 4 because of your slope 1/4. Same as for going down except down 1 over 4. Hope this helped:)
Answer:
0
1
Step-by-step explanation:
First question:
You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.
The sine function can never equal 2, so there is no triangle in this case.
Answer: no triangle
Second question:
You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.
One triangle exists for sure. Now we see if there is a second one.
Now we look at the supplement of angle C.
m<C = 52.5°
supplement of angle C: m<C' = 180° - 52.5° = 127.5°
We add the measures of angles B and the supplement of angle C:
m<B + m<C' = 63° + 127.5° = 190.5°
Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.
Answer: one triangle
