Positive value of x for the given function 2h(x) = log₂(x² +2) is equal to √62.
As given in the question,
Function h is given by : 2h(x) = log₂(x² +2)
Using the definition of logarithm function
aˣ = y
⇒x= logₐy
For h(x) =3, Apply definition of logarithm function we get,
2× 3 = log₂(x² +2)
⇒6= log₂(x² +2)
⇒2⁶ = x² +2
⇒x² = 64-2
⇒x²= 62
⇒x = √62
Therefore, positive value of x for the given function 2h(x) = log₂(x² +2) is equal to √62.
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Answer:The formula y=kxn y = k x n is used for direct variation. The value k is a nonzero constant greater than zero and is called the constant of variation.
Step-by-step explanation:
Just put it depends if they’re in a rush anything is possible
Answer:By definition, perpendicular line are two lines that intersect at right angles. In other words, the angle made by two lines should be 90°. Therefore, the use of distance formula does not help because it only tells you if the sides are equal. It does not tell you about the intercepted angle.
A technique that can help you to know if two straight lines are perpendicular is is you find their slopes. Let's say the slope of line 1 is m1 and the slope of line 2 is m2. If m1*m2 yields a product of -1, then the lines are perpendicular. This is because if m1 is the negative reciprocal of m2, the lines are perpendicular. But if m1=m2, the lines are parallel, meaning they don't intersect at all.
Therefore, the answer is: Find the slopes and show that their product is -1.
hope it help