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Lady bird [3.3K]
3 years ago
9

A company has to buy computers and printers. Each computer, x, costs $585 and each printer, y, costs $385. If the company spends

$7,575 and buys a total of 15 machines, how many of each did it buy?
Mathematics
1 answer:
Luden [163]3 years ago
6 0

The company bought 9 computers and 6 printers

<em><u>Solution:</u></em>

Let "x" be the number of computers bought

Let "y" be the number of printers bought

cost of 1 computer = $ 585

cost of 1 printer = $ 385

<em><u>The company buys a total of 15 machines</u></em>

Therefore, we can frame a equation as:

number of computers bought + number of printers bought = 15

x + y = 15 ------ eqn 1

<em><u>The company spends $7,575</u></em>

Therefore, we can frame a equation as:

number of computers bought x cost of 1 computer + number of printers bought x cost of 1 printer = 7575

x \times 585 + y \times 385 = 7575

585x + 385y = 7575 ------ eqn 1

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

x = 15 - y --------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

585(15 - y) + 385y = 7575

8775 - 585y + 385y = 7575

-200y = 7575 - 8775

-200y = -1200

y = 6

<em><u>Substitute y = 6 in eqn 3</u></em>

x = 15 - 6

x = 9

Thus the company bought 9 computers and 6 printers

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