Answer:
![35 {z}^{6} {d}^{11}](https://tex.z-dn.net/?f=35%20%7Bz%7D%5E%7B6%7D%20%7Bd%7D%5E%7B11%7D%20)
Step-by-step explanation:
Assuming you are supposed to simplify:
![7 {z}^{2} \times 5 {z}^{4} \times {d}^{3} \times {d}^{8}](https://tex.z-dn.net/?f=7%20%7Bz%7D%5E%7B2%7D%20%20%5Ctimes%205%20%7Bz%7D%5E%7B4%7D%20%20%5Ctimes%20%20%7Bd%7D%5E%7B3%7D%20%20%5Ctimes%20%20%7Bd%7D%5E%7B8%7D%20)
Then we need to apply the product rule of indices.
![{a}^{m} \times {a}^{n} = {a}^{m + n}](https://tex.z-dn.net/?f=%20%7Ba%7D%5E%7Bm%7D%20%20%5Ctimes%20%20%7Ba%7D%5E%7Bn%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%20%2B%20n%7D%20)
So we multiply to get:
![35 {z}^{2 + 4} \times {d}^{3 + 8}](https://tex.z-dn.net/?f=35%20%7Bz%7D%5E%7B2%20%2B%204%7D%20%20%5Ctimes%20%20%7Bd%7D%5E%7B3%20%2B%208%7D%20)
We now simplify the exponents to get:
![35 {z}^{6} \times {d}^{11}](https://tex.z-dn.net/?f=35%20%7Bz%7D%5E%7B6%7D%20%20%5Ctimes%20%20%7Bd%7D%5E%7B11%7D%20)
Therefore the required product is
![35 {z}^{6} {d}^{11}](https://tex.z-dn.net/?f=35%20%7Bz%7D%5E%7B6%7D%20%7Bd%7D%5E%7B11%7D%20)
Answer:
32'cube
Step-by-step explanation:
Just i have no paper and pen so i just calculated it in my mind so its not practically an accurate answer
Answer:
The Answer is (1,10)
Step-by-step explanation:
First, I saw the operation done on point (5,8), to translate it to point (3,9), then I did this operation again to get the answer.
[The operation I'm talking about is (x-2,y+1)]
It will always be zero. Try plugging in a number for X. Let's say it's 1. So 6(1) - 6(1).... 6 - 6=0. Try some other values for you to prove it.
Answer:
a= -15/8
Step-by-step explanation: