All categories

3 years ago

Where do martians leave thier spaceships

Mathematics

2 answers:

kari74 [83]3 years ago

8 0

They leave it on the moon.

saveliy_v [14]3 years ago

4 0

Or know where because as far as we know there are no martians

You might be interested in

Anyone knows the slope of this graph?

ehidna [41]

It’s Y=2/1x-0 aka y=2x-0

3 0

3 years ago

Determine the exact value of sin 240

iren2701 [21]

simplify : the exact value of sin 240

Explanation: sin(240)=sin(60+180)=-sin60

$\begin{gathered} -sin60=-\frac{\sqrt{3}}{2} \\ =-0.87 \end{gathered}$

Final answer: the required vaalue of the sin 240 is -0.87

7 0

1 year ago

In triangle ABC a=39 m,b=27 m and c = 42 m. Find the area

Agata [3.3K]

Answer:

MY BRAIN CANT PROCESS THIS!!!!

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2

andrey2020 [161]

Answer:

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

Step-by-step explanation:

Consider the provided matrix.

$v_1=\begin{bmatrix}-3\\1 \end{bmatrix}$

$v_2=\begin{bmatrix}-1\\1 \end{bmatrix}$

$\lambda_1=4, \lambda_2=2$

The general solution of the equation $x'=Ax$

$x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}$

Substitute the respective values we get:

$x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}$

Substitute initial condition $x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}$

$\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}$

Reduce matrix to reduced row echelon form.

$\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}$

Therefore, $c_1=2.5,c_2=1.5$

Thus, the general solution of the equation $x'=Ax$

$x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}$

$x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

The required position of the particle at time t is: $x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}$

6 0

3 years ago

The sum of two consecutive mile markers on the interstate is 417417. Find the numbers on the markers

noname [10]

Hello from MrBillDoesMath!

Answer:

The first marker is labeled 208708; the second (consecutive) one 208709

Discussion:

Call the first mile marker "m". Then

m + (m+1) = 417417 => combine like terms

2m + 1 = 417417 => subtract 1 from both sides

2m = 417416 => divide both sides by 2

m = 417416/2 = 208708

Note: m and (m+1) are consecutive as they immediately follow each other in the set of integers.

Thank you,

MrB

5 0

3 years ago