Ask question

Ask question

All categories

3 years ago

12

Estimate the sum or difference use the benchmarks 0 1/2 1

1 answer:

ANEK [815]3 years ago

3 0

Well, sum means adding. So adding it all together, I got 2.83 with the 3 repeating

You might be interested in

borishaifa [10]

Like a first step bc. there is a denominator this will be more usefully eliminate it so what you can make it multiplied both sides by 2
- so will get

-2/2x +2*3/2 = 2(-4x+7)/2

(-2x +6)/2 = 2(-4x+7)/2 common denominator the 2 so make the numerators equal and solve for x

-2x+6=-8x+14

6x=8

hope helped

5 0

3 years ago

Which fraction is greater 5 1/4 and 5 5/6

spayn [35]

5 5/6

Cause .25 + 5 is smaller than 5/6 + 5

3 0

2 years ago

Read 2 more answers

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2

butalik [34]

To solve this question, we use the factor theorem, and using it, the polynomial function is:

$f(x) = x^3 - 2x^2 - 3x + 6$

------------------------------

The factor theorem means that if k is a root of f(x), f(k) = 0.

Thus, applying the factor theorem for this question, we have to choose the function for which: $f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0$

------------------------------

Function 1:

$f(x) = x^3 - 2x^2 - 3x + 6$

Testing the values:

$f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0$

$f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0$

$f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0$

Thus, since all three conditions are satisfied, $f(x) = x^3 - 2x^2 - 3x + 6$ is the polynomial function.

A similar question is given at brainly.com/question/11378552

5 0

3 years ago

Write (4n^4)^2 without exponents

Verdich [7]

Answer:

(4nx4nx4nx4n)x(4nx4nx4nx4n)

5 0

2 years ago

Let f(x) = - 10x + 9 and g(x) = x2 + 12 <br>Find f( - 4)/g( - 4)

Reptile [31]

Answer:

$\frac{49}{28}$

Step-by-step explanation:

Evaluate g(- 4) and f(- 4) by substituting x = - 4 into g(x) and f(x), that is

f(- 4) = - 10(- 4) + 9 = 40 + 9 = 49

g(- 4) = (- 4)² + 12 = 16 + 12 = 28

Then

$\frac{f(-4)}{g(-4)}$ = $\frac{49}{28}$ = $\frac{7}{4}$

7 0

3 years ago