Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10

10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7

Answer: D
Step-by-step explanation: A is not possible because the shape and the way it is drawn is nearly the same as the figure given. The shape of B is different from the given shape. C is a little too flat to be considered symmetrical to the figure. Which leaves only option D.
Hope this helped :D
Answer:
Step-by-step explanation:

Multiply the equation by 4

5x - 2 + 2 = 2*(3y + 2)
5x +0 = 2*3y + 2*2
5x = 6y + 4
5x - 6y = 4 --------------------(I)

Multiply the equation by 6

2*(7y + 3) = 3x + 2*7
14y + 6 = 3x + 14
14y = 3x + 14 - 6
14y = 3x + 8
-3x + 14y = 8 ------------------------(II)
Multiply equation (I) by 3 and equation (II) by 5 and then add
(I)*3 15x - 18y = 12
(II)*5 <u>-15x + 70y = 40</u> {Now add}
52y = 52
y = 52/52
y = 1
Substitute y =1 in equation (I)
5x - 6*1 = 4
5x - 6 = 4
5x = 4 +6
5x = 10
x = 10/5
x = 2
Answer:
55%
Step-by-step explanation:
11/20 = 0.55
0.55 = 55%
Answer: 6.75 feet
Step-by-step explanation:
Since, the ratio of the side of the similar triangle = 2 : 3
Thus, by the property of similar triangle,
The ratio of the altitudes of the triangle = 2 : 3
Let the altitude of smaller triangle = 2 x
And, the altitude of larger triangle = 3 x
Where x is any number.
According to the question,
2 x = 4.5
x = 2.25
Therefore, the altitude of larger triangle = 3 × 2.25 = 6.75 feet